1=(12x^2)-14x-48

Solution for 1=(12x^2)-14x-48 equation:

1=(12x^2)-14x-48

We move all terms to the left:

1-((12x^2)-14x-48)=0

We get rid of parentheses

-12x^2+14x+48+1=0

We add all the numbers together, and all the variables

-12x^2+14x+49=0

a = -12; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·(-12)·49
Δ = 2548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2548}=\sqrt{196*13}=\sqrt{196}*\sqrt{13}=14\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{13}}{2*-12}=\frac{-14-14\sqrt{13}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{13}}{2*-12}=\frac{-14+14\sqrt{13}}{-24}
$